The bulk of my articles will probably continue to be on the subjects of Mathematics and Subversion and are marked with those categories.

I have tried to keep to purely technical matters. Occasionally I might express an opinion or a personal preference; I try to mark such material with the category Subjective. When I write about software or documents that I think are useful, these are instead marked with References.

Much of what I write is a clarification or re-organisation of well-known material. When I have written about something new, however trivial or otherwise, I have used the Research category; it is unlikely that this material is ground-breaking or previously unknown, but it is original to me.

When an post is intended to be a memory aid, or a method to help check a half-remembered fact or formula, I use the Mnemonics category.

The Example category is used for posts containing only a worked example, perhaps with a link to another post.

When an article contains a query regarding something about which I have not been able to find out, or a problem that I have only been able partially to solve, then it is marked with the Question / Unsolved category.

Many of my categories have finer subcategories. (I may not break Mathematics into further subcategories, as much of what I write about is algebraic, combinatorial or other formal manipulation.)

Some of my categories are rather broad. For example, I just lump Astronomy in with Cosmology.


2 Responses to “Categories”

  1. Jess Tauber Says:

    Hi- have a question that might be right up your alley- I’m interested in summed pairs of triangular numbers where you can define them as pairs of every Nth triangular. Obviously every 1st will be squares, but what about every 2nd, 3rd and so on. I’ve found these in mathematical work on atomic nuclei, in relation to so-called ‘magic’ numbers. Thanks. Jess Tauber

  2. Rob Says:


    Write T(n) = n(n+1)/2 for the n^th triangular number.

    Then T(n) + T(n-1) = n(n+1)/2 + n(n-1)/2 = n^2.

    Is this what you mean by “2nd”?:
    T(n) + T(n-2) = n(n+1)/2 + (n-1)(n-2)/2 = (1/2) [n^2 + n + n^2 – 3n + 2] = n^2 – (n-1)
    which might be pictured as an n × n square with an off-diagonal missing. I can’t see a simpler geometric interpretation for such numbers.

Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out /  Change )

Google+ photo

You are commenting using your Google+ account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )


Connecting to %s

This site uses Akismet to reduce spam. Learn how your comment data is processed.

%d bloggers like this: